NaOH · 40.00 g/mol
C₁₆H₃₃(CH₃)₃N⁺
H₂SO₄ ——→ 2H⁺ + SO₄²⁻
pH = -log[H⁺]
NaOCl + H₂O ⇌
Ca(OH)₂ · 74.09
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